A compound forms Hexagonal close packed structure what is the total number of voids in 0.5 mol of it

Q- A Compound forms Hexagonal close packed structure. What is the total number of voids in 0.5 mol of it? How many of these are tetrahedral voids?

Answer- Number of Atoms in 0.5 mol = 0.5 x 6.022 x 1023

= 3.022 x 1023 atoms

Number of Octahedral Voids = Number of Atoms

Number of Atoms = 3.022 x 1023 atoms

Now, According to Question,

Number of Tetrahedral Voids = 2 x Number of Atoms

= 2 x 3.022 x 1023

= 6.022 x 1023

Total Number of Voids in 0.5 mol = 3.011 x 1023 + 6.022 x 1023

= 9.033 x 1023

Therefore, the total number of Tetrahedral Voids = 6.022 x 1023 Answer.

The Total Number of Voids in 0.5 mol = 9.033 x 1023 Answer.

Some Important Questions for Class 12th

  1. What is the two-dimensional coordination number of a molecule in square close-packed layer?
  2. Name the parameters that characterise a unit cell

Students Also Asks

What is the total number of voids in 0.5 mole of hexagonal close packed structure?

The total number of voids in 0.5 moles of hexagonal close-packed structure is equal to 9.033 x 1023. But the solution and method to find it out are given in the following post.

A compound forms hexagonal close-packed structure what is the total number of voids in 0.5 mol of it

If a compound forms a Hexagonal close-packed structure then the total number of voids in 0.5 mol of it will be 9.033 x 1023 and the number of tetrahedral voids will be 6.022 x 1023. For more details solution you can see the link given.

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