Q- **A Compound forms Hexagonal close packed structure. What is the total number of voids in 0.5 mol of it? How many of these are tetrahedral voids?**

Answer- Number of Atoms in 0.5 mol = 0.5 x 6.022 x 10^{23}

= 3.022 x 10^{23} atoms

Number of Octahedral Voids = Number of Atoms

Number of Atoms = 3.022 x 10^{23} atoms

Now, According to Question,

**Number of Tetrahedral Voids** = 2 x Number of Atoms

= 2 x 3.022 x 10^{23}

= 6.022 x 10^{23}

**Total Number of Voids in 0.5 mol** = 3.011 x 10^{23} + 6.022 x 10^{23}

= 9.033 x 10^{23}

Therefore, the total number of Tetrahedral Voids = 6.022 x 10^{23} **Answer.**

The Total Number of Voids in 0.5 mol = 9.033 x 10^{23} **Answer.**

### Some Important Questions for Class 12th

- What is the two-dimensional coordination number of a molecule in square close-packed layer?
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### Students Also Asks

### What is the total number of voids in 0.5 mole of hexagonal close packed structure?

The total number of voids in 0.5 moles of hexagonal close-packed structure is equal to 9.033 x 1023. But the solution and method to find it out are given in the following post.

### A compound forms hexagonal close-packed structure what is the total number of voids in 0.5 mol of it

If a compound forms a Hexagonal close-packed structure then the total number of voids in 0.5 mol of it will be 9.033 x 10^{23} and the number of tetrahedral voids will be 6.022 x 10^{23}. For more details solution you can see the link given.