Q- **A compound is formed by two elements M and N. The element N forms ccp and atoms of M occupy 1/3rd of tetrahedral voids. What is the formula of the compound?**

Answer- The ccp lattice is formed by atoms of N element. So, the number of tetrahedral voids is equal to twice the number of atoms of the N element.

According to the question,

The atoms of M Element occupy 1/3rd of tetrahedral voids. So, the number of M is equal to 2 x 1/3 = 2/3rd of the atoms of the element N.

Therefore, the ratio of the number of atoms of element M to that of element N is M : N = (2/3):1 = 2:3

Hence, the formula of that compound is M2N3.

### Class 12th Important Questions

- What is the two-dimensional coordination number of a molecule in a square close-packed layer
- Distinguish between: (i) Hexagonal and monoclinic unit cells (ii) Face centered and end-centered unit cell
- Name the parameters that characterise a unit cell

### FAQs

### A compound is formed by two elements M and N the element N forms ccp and atoms of M occupy 1/3rd of

If a compound is formed by two elements M and N and the element N forms ccp and atoms of m occupy 1/3rd of tetrahedral voids then, solving this question numerically we can conclude that the formula of that compound is M2N3. The complete solved answer to this question is in the article.

### A compound is formed by two elements M and N the element N forms ccp

Given that, a compound is formed by two elements M and N and the element N forms ccp where M element occupies 1/3rd of tetrahedral voids. In this case, we need to solve this question, the number of M is equal to 2 x 1/3 = 2/3rd of the atoms of the element N. Then, M : N = (2/3):1 = 2:3. So, formula of compound = M2N3